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Atmospheric absorption/scattering of sunlight Anonymous 18/07/27(Fri)04:35 No. 16685 ID: 953c1f
16685

File 153265890490.png - (96.72KB , 620x359 , solar-panels-australia.png )

Hey, /sci/. I'm running a simulation of solar panel efficiency and I need some way to calculate energy production from the sun's position in the sky. For example, assuming a panel that is always pointer at the sun, when the sun is closer to the horizon the panel will generate less energy than when it's high in the sky.

I'm looking for something like f(x radians) = y W/m^2.

Thanks.


>>
Anonymous 18/07/27(Fri)04:50 No. 16686 ID: 953c1f
16686

File 15326598517.png - (21.74KB , 1115x717 , theta.png )

Here's part of what I'm doing. Assuming a panel can rotate side to side and track the sun, but cannot rotate up and down, these are the angles of inclination of the panel for a given latitude that will yield the maximum energy production throughout the year. The problem is that this assumes that as long as you point the panel directly at the sun, you will generate the same amount of power at noon as you would just before dusk. So for example at the equator the optimal angle is predicted to be 42°, rather than something flatter. At the same time, energy production is predicted to be higher in Antarctica (99% efficiency) than at the equator (92%), which is nonsense.




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